Optimal. Leaf size=184 \[ \frac {b (A b-2 a B) \sqrt {a+b x^2}}{32 a x^6}+\frac {b^2 (A b-2 a B) \sqrt {a+b x^2}}{128 a^2 x^4}-\frac {3 b^3 (A b-2 a B) \sqrt {a+b x^2}}{256 a^3 x^2}+\frac {(A b-2 a B) \left (a+b x^2\right )^{3/2}}{16 a x^8}-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}}+\frac {3 b^4 (A b-2 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{256 a^{7/2}} \]
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Rubi [A]
time = 0.10, antiderivative size = 184, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 6, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {457, 79, 43, 44,
65, 214} \begin {gather*} \frac {3 b^4 (A b-2 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{256 a^{7/2}}-\frac {3 b^3 \sqrt {a+b x^2} (A b-2 a B)}{256 a^3 x^2}+\frac {b^2 \sqrt {a+b x^2} (A b-2 a B)}{128 a^2 x^4}+\frac {\left (a+b x^2\right )^{3/2} (A b-2 a B)}{16 a x^8}+\frac {b \sqrt {a+b x^2} (A b-2 a B)}{32 a x^6}-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}} \end {gather*}
Antiderivative was successfully verified.
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Rule 43
Rule 44
Rule 65
Rule 79
Rule 214
Rule 457
Rubi steps
\begin {align*} \int \frac {\left (a+b x^2\right )^{3/2} \left (A+B x^2\right )}{x^{11}} \, dx &=\frac {1}{2} \text {Subst}\left (\int \frac {(a+b x)^{3/2} (A+B x)}{x^6} \, dx,x,x^2\right )\\ &=-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}}+\frac {\left (-\frac {5 A b}{2}+5 a B\right ) \text {Subst}\left (\int \frac {(a+b x)^{3/2}}{x^5} \, dx,x,x^2\right )}{10 a}\\ &=\frac {(A b-2 a B) \left (a+b x^2\right )^{3/2}}{16 a x^8}-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}}-\frac {(3 b (A b-2 a B)) \text {Subst}\left (\int \frac {\sqrt {a+b x}}{x^4} \, dx,x,x^2\right )}{32 a}\\ &=\frac {b (A b-2 a B) \sqrt {a+b x^2}}{32 a x^6}+\frac {(A b-2 a B) \left (a+b x^2\right )^{3/2}}{16 a x^8}-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}}-\frac {\left (b^2 (A b-2 a B)\right ) \text {Subst}\left (\int \frac {1}{x^3 \sqrt {a+b x}} \, dx,x,x^2\right )}{64 a}\\ &=\frac {b (A b-2 a B) \sqrt {a+b x^2}}{32 a x^6}+\frac {b^2 (A b-2 a B) \sqrt {a+b x^2}}{128 a^2 x^4}+\frac {(A b-2 a B) \left (a+b x^2\right )^{3/2}}{16 a x^8}-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}}+\frac {\left (3 b^3 (A b-2 a B)\right ) \text {Subst}\left (\int \frac {1}{x^2 \sqrt {a+b x}} \, dx,x,x^2\right )}{256 a^2}\\ &=\frac {b (A b-2 a B) \sqrt {a+b x^2}}{32 a x^6}+\frac {b^2 (A b-2 a B) \sqrt {a+b x^2}}{128 a^2 x^4}-\frac {3 b^3 (A b-2 a B) \sqrt {a+b x^2}}{256 a^3 x^2}+\frac {(A b-2 a B) \left (a+b x^2\right )^{3/2}}{16 a x^8}-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}}-\frac {\left (3 b^4 (A b-2 a B)\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,x^2\right )}{512 a^3}\\ &=\frac {b (A b-2 a B) \sqrt {a+b x^2}}{32 a x^6}+\frac {b^2 (A b-2 a B) \sqrt {a+b x^2}}{128 a^2 x^4}-\frac {3 b^3 (A b-2 a B) \sqrt {a+b x^2}}{256 a^3 x^2}+\frac {(A b-2 a B) \left (a+b x^2\right )^{3/2}}{16 a x^8}-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}}-\frac {\left (3 b^3 (A b-2 a B)\right ) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x^2}\right )}{256 a^3}\\ &=\frac {b (A b-2 a B) \sqrt {a+b x^2}}{32 a x^6}+\frac {b^2 (A b-2 a B) \sqrt {a+b x^2}}{128 a^2 x^4}-\frac {3 b^3 (A b-2 a B) \sqrt {a+b x^2}}{256 a^3 x^2}+\frac {(A b-2 a B) \left (a+b x^2\right )^{3/2}}{16 a x^8}-\frac {A \left (a+b x^2\right )^{5/2}}{10 a x^{10}}+\frac {3 b^4 (A b-2 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{256 a^{7/2}}\\ \end {align*}
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Mathematica [A]
time = 0.28, size = 142, normalized size = 0.77 \begin {gather*} -\frac {\sqrt {a+b x^2} \left (15 A b^4 x^8-10 a b^3 x^6 \left (A+3 B x^2\right )+4 a^2 b^2 x^4 \left (2 A+5 B x^2\right )+32 a^4 \left (4 A+5 B x^2\right )+16 a^3 b x^2 \left (11 A+15 B x^2\right )\right )}{1280 a^3 x^{10}}+\frac {3 b^4 (A b-2 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{256 a^{7/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(325\) vs.
\(2(156)=312\).
time = 0.10, size = 326, normalized size = 1.77
method | result | size |
risch | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (15 A \,b^{4} x^{8}-30 B a \,b^{3} x^{8}-10 A a \,b^{3} x^{6}+20 B \,a^{2} b^{2} x^{6}+8 A \,a^{2} b^{2} x^{4}+240 B \,a^{3} b \,x^{4}+176 A \,a^{3} b \,x^{2}+160 B \,a^{4} x^{2}+128 A \,a^{4}\right )}{1280 x^{10} a^{3}}+\frac {3 b^{5} \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right ) A}{256 a^{\frac {7}{2}}}-\frac {3 b^{4} \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right ) B}{128 a^{\frac {5}{2}}}\) | \(172\) |
default | \(B \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{8 a \,x^{8}}-\frac {3 b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{6 a \,x^{6}}-\frac {b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{4 a \,x^{4}}+\frac {b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{2 a \,x^{2}}+\frac {3 b \left (\frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}}}{3}+a \left (\sqrt {b \,x^{2}+a}-\sqrt {a}\, \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right )\right )\right )}{2 a}\right )}{4 a}\right )}{6 a}\right )}{8 a}\right )+A \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{10 a \,x^{10}}-\frac {b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{8 a \,x^{8}}-\frac {3 b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{6 a \,x^{6}}-\frac {b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{4 a \,x^{4}}+\frac {b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{2 a \,x^{2}}+\frac {3 b \left (\frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}}}{3}+a \left (\sqrt {b \,x^{2}+a}-\sqrt {a}\, \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right )\right )\right )}{2 a}\right )}{4 a}\right )}{6 a}\right )}{8 a}\right )}{2 a}\right )\) | \(326\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.28, size = 294, normalized size = 1.60 \begin {gather*} -\frac {3 \, B b^{4} \operatorname {arsinh}\left (\frac {a}{\sqrt {a b} {\left | x \right |}}\right )}{128 \, a^{\frac {5}{2}}} + \frac {3 \, A b^{5} \operatorname {arsinh}\left (\frac {a}{\sqrt {a b} {\left | x \right |}}\right )}{256 \, a^{\frac {7}{2}}} + \frac {{\left (b x^{2} + a\right )}^{\frac {3}{2}} B b^{4}}{128 \, a^{4}} + \frac {3 \, \sqrt {b x^{2} + a} B b^{4}}{128 \, a^{3}} - \frac {{\left (b x^{2} + a\right )}^{\frac {3}{2}} A b^{5}}{256 \, a^{5}} - \frac {3 \, \sqrt {b x^{2} + a} A b^{5}}{256 \, a^{4}} - \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} B b^{3}}{128 \, a^{4} x^{2}} + \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} A b^{4}}{256 \, a^{5} x^{2}} - \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} B b^{2}}{64 \, a^{3} x^{4}} + \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} A b^{3}}{128 \, a^{4} x^{4}} + \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} B b}{16 \, a^{2} x^{6}} - \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} A b^{2}}{32 \, a^{3} x^{6}} - \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} B}{8 \, a x^{8}} + \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} A b}{16 \, a^{2} x^{8}} - \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} A}{10 \, a x^{10}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.59, size = 317, normalized size = 1.72 \begin {gather*} \left [-\frac {15 \, {\left (2 \, B a b^{4} - A b^{5}\right )} \sqrt {a} x^{10} \log \left (-\frac {b x^{2} + 2 \, \sqrt {b x^{2} + a} \sqrt {a} + 2 \, a}{x^{2}}\right ) - 2 \, {\left (15 \, {\left (2 \, B a^{2} b^{3} - A a b^{4}\right )} x^{8} - 10 \, {\left (2 \, B a^{3} b^{2} - A a^{2} b^{3}\right )} x^{6} - 128 \, A a^{5} - 8 \, {\left (30 \, B a^{4} b + A a^{3} b^{2}\right )} x^{4} - 16 \, {\left (10 \, B a^{5} + 11 \, A a^{4} b\right )} x^{2}\right )} \sqrt {b x^{2} + a}}{2560 \, a^{4} x^{10}}, \frac {15 \, {\left (2 \, B a b^{4} - A b^{5}\right )} \sqrt {-a} x^{10} \arctan \left (\frac {\sqrt {-a}}{\sqrt {b x^{2} + a}}\right ) + {\left (15 \, {\left (2 \, B a^{2} b^{3} - A a b^{4}\right )} x^{8} - 10 \, {\left (2 \, B a^{3} b^{2} - A a^{2} b^{3}\right )} x^{6} - 128 \, A a^{5} - 8 \, {\left (30 \, B a^{4} b + A a^{3} b^{2}\right )} x^{4} - 16 \, {\left (10 \, B a^{5} + 11 \, A a^{4} b\right )} x^{2}\right )} \sqrt {b x^{2} + a}}{1280 \, a^{4} x^{10}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.61, size = 212, normalized size = 1.15 \begin {gather*} \frac {\frac {15 \, {\left (2 \, B a b^{5} - A b^{6}\right )} \arctan \left (\frac {\sqrt {b x^{2} + a}}{\sqrt {-a}}\right )}{\sqrt {-a} a^{3}} + \frac {30 \, {\left (b x^{2} + a\right )}^{\frac {9}{2}} B a b^{5} - 140 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} B a^{2} b^{5} + 140 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} B a^{4} b^{5} - 30 \, \sqrt {b x^{2} + a} B a^{5} b^{5} - 15 \, {\left (b x^{2} + a\right )}^{\frac {9}{2}} A b^{6} + 70 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} A a b^{6} - 128 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} A a^{2} b^{6} - 70 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} A a^{3} b^{6} + 15 \, \sqrt {b x^{2} + a} A a^{4} b^{6}}{a^{3} b^{5} x^{10}}}{1280 \, b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 2.14, size = 205, normalized size = 1.11 \begin {gather*} \frac {3\,A\,a\,\sqrt {b\,x^2+a}}{256\,x^{10}}-\frac {11\,B\,{\left (b\,x^2+a\right )}^{3/2}}{128\,x^8}-\frac {7\,A\,{\left (b\,x^2+a\right )}^{3/2}}{128\,x^{10}}+\frac {3\,B\,a\,\sqrt {b\,x^2+a}}{128\,x^8}-\frac {A\,{\left (b\,x^2+a\right )}^{5/2}}{10\,a\,x^{10}}+\frac {7\,A\,{\left (b\,x^2+a\right )}^{7/2}}{128\,a^2\,x^{10}}-\frac {3\,A\,{\left (b\,x^2+a\right )}^{9/2}}{256\,a^3\,x^{10}}-\frac {11\,B\,{\left (b\,x^2+a\right )}^{5/2}}{128\,a\,x^8}+\frac {3\,B\,{\left (b\,x^2+a\right )}^{7/2}}{128\,a^2\,x^8}-\frac {A\,b^5\,\mathrm {atan}\left (\frac {\sqrt {b\,x^2+a}\,1{}\mathrm {i}}{\sqrt {a}}\right )\,3{}\mathrm {i}}{256\,a^{7/2}}+\frac {B\,b^4\,\mathrm {atan}\left (\frac {\sqrt {b\,x^2+a}\,1{}\mathrm {i}}{\sqrt {a}}\right )\,3{}\mathrm {i}}{128\,a^{5/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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